5x^2-2x+1=0

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Solution for 5x^2-2x+1=0 equation:


Simplifying
5x2 + -2x + 1 = 0

Reorder the terms:
1 + -2x + 5x2 = 0

Solving
1 + -2x + 5x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
0.2 + -0.4x + x2 = 0

Move the constant term to the right:

Add '-0.2' to each side of the equation.
0.2 + -0.4x + -0.2 + x2 = 0 + -0.2

Reorder the terms:
0.2 + -0.2 + -0.4x + x2 = 0 + -0.2

Combine like terms: 0.2 + -0.2 = 0.0
0.0 + -0.4x + x2 = 0 + -0.2
-0.4x + x2 = 0 + -0.2

Combine like terms: 0 + -0.2 = -0.2
-0.4x + x2 = -0.2

The x term is -0.4x.  Take half its coefficient (-0.2).
Square it (0.04) and add it to both sides.

Add '0.04' to each side of the equation.
-0.4x + 0.04 + x2 = -0.2 + 0.04

Reorder the terms:
0.04 + -0.4x + x2 = -0.2 + 0.04

Combine like terms: -0.2 + 0.04 = -0.16
0.04 + -0.4x + x2 = -0.16

Factor a perfect square on the left side:
(x + -0.2)(x + -0.2) = -0.16

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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